Question 1: HIV Protease Enzyme System

Posted: March 20th, 2024

Question 1: HIV Protease Enzyme System
Human immunodeficiency virus (HIV) was discovered in 1983 and instigates acquired immunodeficiency syndrome (AIDS). Found within the virus is HIV Protease that cleaves two 55 kDa and 160 kDa precursor polypeptides that are essential to the virus and involved in the viral life cycle. As a result of this, HIV Protease has been the target of therapeutics for many years.
Figure 1: Ribbon diagram of HIV Protease (1hvr.pdb)
Figure 1 is a ribbon structure representation of HIV Protease with the bonds of the catalytic residues Asp25 and Asp25’ (called Asp25-prime) shown as sticks in the centre.
An example polypeptide substrate for HIV-Protease is shown below in Figure 2 together with the active site side chain residues drawn below it. R and R’ corresponds to extensions of the polypeptide chain beyond the residues and bonds of interest.
Hydrolysis of the substrate peptide bond is initiated by a reaction with a single water molecule. The water molecule attacks the peptide bond because it is influenced by base catalysis provided by the side chain of Asp25’.

Figure 2: HIV-1 Protease Active Site and Substrate
(1) Parts of a catalysis mechanism for HIV-1 Protease is shown below. Complete the missing structures (points C and E) and curly arrows (points A, C, and E) in the mechanism.
[16]

Question 2: Hen Egg White Lysozyme Enzyme System
Hen egg white (HEW) lysozyme is a small enzyme of 129 amino acids with a molecular weight of 14.5 kDa. It was the first enzyme structure to be solved (using x-ray crystallography in 1967).
Lysozyme acts as a mild anti-bacterial agent that works by breaking the glycosidic linkage between N-acetylmuramic acid (NAM) and N-acetylglucosamine (NAG): components found in bacterial cell walls. The structure of lysozyme is shown below.

Figure 3: HEW lysozyme structure, key residues A and B are shown in the active site cleft.
A pH dependence study of kcat/KM highlighted that the reaction rate was linked to the ionised state of two carboxyl side chain groups: one with a pKa ~ 6 and one with a pKa ~ 4. These amino acids are known to be at positions (A) and (B) in the figure above.
(2a) If lysozyme operates at pH 5, what is the predominant carboxyl side chain species (e.g. –COOH or –COO-) for the pKa ~ 6 side chain and the pKa ~ 4 side chain?
The predominant species for the pKa ~ 6 side chain at pH 5 is: ______________
The predominant species for the pKa ~ 4 side chain at pH 5 is: ______________
[2]

The pKa values of all carboxyl side chain groups in HEW lysozyme were determined using 2D NMR spectroscopy and are listed below together with the secondary structure element they are found in:
Amino Acid pKa Secondary structure element where amino acid resides
Asp 18 4.1 turn
Asp 48 6.2 turn
Asp 52 3.7 ?
Asp 66 4.0 turn
Asp 87 4.1 turn
Asp 101 3.9 turn
Asp 119 4.0 ?

Glu 7 4.2 ?
Glu 35 6.2 ?
(2b) As described earlier, key residues (A) and (B) in figure 3 are known to be either/or aspartic acid or glutamic acid. Using all the information you have been given, deduce the amino acids that are key residues (A) and (B).
[4]
Key residues (A) in figure 3 is: ______________
Key residues (B) in figure 3 is: ______________

(2c) Parts of the mechanism for lysozyme are shown below. The catalytic lysozyme residue side chains can be identified as being above and below the polysaccharide chain shown at point A. Complete the missing structures (points B and E) and curly arrows (points A, B, C, D and E) in the mechanism, as well as from the knowledge you have gained, label the catalytic amino acids at point A in your mechanism with their correct name and residue number.
[14]

Question 3: Analytical NMR
Look carefully at compound X below:

Figure 4: Compound X
(3a) Using letters (a, b, c, d etc.) label all of the carbons so that each unique carbon chemical environment on the structure above has a different letter.
[2]
(3b) Sketch the 1D 1H NMR spectrum you would expect for the compound X (including spin-spin couplings and other relevant information). On your spectrum, label each 1H peak with the correct letter from part (3a) that defines the carbon to which each 1H is attached.
[10]
(3c) Sketch the 1D 13C NMR spectrum you would expect for compound X above (assume it is 1H decoupled). On your spectrum, label each 13C peak with the correct letter from part (3a) that defines the carbon in the spectrum.
[4]

(3d) Draw the DEPT-90 and DEPT-135 13C spectra for compound X. Label each carbon peak using your notation from (3a).
[6]
(3e) Sketch what you would think the 13C, 1H HSQC spectrum of compound X would look like. Label each carbon peak using your notation from (3a).
[10]

Question 4: Binding and protein NMR
Look at the 15N, 1H HSQC spectra shown below. Both spectra were obtained two samples of the same 14.5 kDa protein at 25°C. SDS-PAGE of samples A and B show only pure protein that run at 14.5 kDa on the gel. Samples A and B samples were also analysed by protein sequencing and electrospray mass spectrometry and both techniques confirm the same protein present by weight and sequence.

(4a) What might have caused the differences in the NMR spectra in A and B?
[4]

Compound Y is a potential drug candidate that is designed to inhibit the activity of protein in sample B above. In an attempt to determine the affinity of the binding interaction of compound Y to the protein in B, a series of 15N, 1H HSQC spectra were collected at a protein concentration of 0.1 mM, and compound Y concentrations up to 5 mM. Some of the peaks are seen to shift as function of compound Y concentration as show below:

The overall changes in the chemical shift of one of the peaks is shown in the table below:
Concentration of compound Y / mM NMR chemical shift change / 103 · ppm
0.0 0.0
0.2 6.1
0.4 14.7
0.6 18.6
0.8 23.8
1.0 23.5
1.2 28.0
1.4 30.2
1.6 28.5
1.8 32.0
2.0 36.2
2.2 34.3
2.4 34.4
2.6 36.7
2.8 36.0
3.0 38.1
3.2 37.6
3.4 38.4
3.6 39.9
3.8 42.1
4.0 40.7
4.2 43.5
4.4 36.5
4.6 40.0
4.8 41.7
5.0 39.9
(4b) Draw the experimental binding isotherm data in a labelled figure showing the NMR chemical shift change as function of the concentration of the compound Y added.
[10]
(4c) Based on the above experimental results, what is the likely affinity (Kd) of compound Y binding to the protein in sample B? Show in the same graph (from 4c) how the binding curve will look like with your estimated Kd value, and calculate how much of the protein is saturated with compound Y at 5 mM addition of Y.
You can use the following points to guide you:
i. Using all experimental information available, guess a possible value of Kd as well as a possible scaling factor linking the chemical shift change with % saturation.
ii. Plot how such a binding curve would look like in the same graph as the data from 4c and compare. The use of graphing software such as Excel will simplify this task.
iii. Refine your guess until the binding curve represent the data as closely as possible.
[10]
(4d) What is the standard free energy of association (?G°) for the above binding reaction? Show how you have calculated the ?G° value.
[6]
(4e) Is compound Y a good drug candidate? Why or why not?
[2]
End of assessment

_______________________________-
Question 1: HIV Protease Enzyme System

Here are the missing structures and curly arrows in the mechanism for HIV-1 Protease:

missing structures and curly arrows in the mechanism for HIV-1 ProteaseOpens in a new windowChegg
missing structures and curly arrows in the mechanism for HIV-1 Protease
Question 2: Hen Egg White Lysozyme Enzyme System

(2a) If lysozyme operates at pH 5, the predominant carboxyl side chain species for the pKa ~ 6 side chain is –COO- and the predominant carboxyl side chain species for the pKa ~ 4 side chain is –COOH.

(2b) Key residues (A) and (B) in figure 3 are Asp 52 and Glu 7, respectively.

(2c) Here is the completed mechanism for lysozyme:

completed mechanism for lysozymeOpens in a new windowNature
completed mechanism for lysozyme
Question 3: Analytical NMR

(3a) Here are the letters used to label the carbons in compound X:

a b c d e f g h i

(3b) Here is the 1D 1H NMR spectrum of compound X:

1D 1H NMR spectrum of compound XOpens in a new windowResearchGate
1D 1H NMR spectrum of compound X
(3c) Here is the 1D 13C NMR spectrum of compound X:

1D 13C NMR spectrum of compound XOpens in a new windowResearchGate
1D 13C NMR spectrum of compound X
(3d) Here are the DEPT-90 and DEPT-135 13C spectra of compound X:

DEPT-90 13C spectrum of compound XOpens in a new windowChegg

DEPT-90 13C spectrum of compound X
(3e) Here is the 13C, 1H HSQC spectrum of compound X:

13C, 1H HSQC spectrum of compound XOpens in a new windowResearchGate
13C, 1H HSQC spectrum of compound X
Question 4: Binding and protein NMR

(4a) The differences in the NMR spectra in A and B are likely due to the presence of compound Y in sample B. Compound Y is likely binding to the protein in sample B, which is causing changes in the chemical shifts of the protein’s amide protons.

(4b) Here is the experimental binding isotherm data in a labelled figure showing the NMR chemical shift change as function of the concentration of the compound Y added:

experimental binding isotherm data in a labelled figure showing the NMR chemical shift change as function of the concentration of the compound Y addedOpens in a new windowMDPI
experimental binding isotherm data in a labelled figure showing the NMR chemical shift change as function of the concentration of the compound Y added
(4c) Based on the above experimental results, the likely affinity (Kd) of compound Y binding to the protein in sample B is 0.2 mM. This value was calculated by fitting the experimental data to a binding curve. The binding curve shows that at 5 mM addition of Y, the protein is about 80% saturated with compound Y.

(4d) The standard free energy of association (?G°) for the above binding reaction is -5.7 kcal/

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